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Solve the equation, showing all steps leading to your answer. Then check your answer to determine if any of the solutions are extraneous. http://prntscr.com/973ixi
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@Directrix
x-5 = sq root(x+1) (x-5)^2 = x +1 X^2 -10x +25 = x +1 X^2 -11x +24 = 0 Quadratic Formula x = [--11 +-sq root(121 -4*1*24)] / 2 x = 11 +-sq root ( 25) / 2 x = 8 x = 3
Does x = 3 work when you run it back through the original equation before both sides were squared? It may be exraneous.
Hmmm it seems x=3 doesn't work.
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