Question

PLEASE help me with coordinate pane someone!
Promise medal and fan!




Use integer values of x from -3 to 3 to graph the equation y = -2x^2 + 3

Please help.

Answer 1

-2x^2+3=0 is a quadratic equation do you know how to plot them

Answer 2

I guess

Answer 3

I don't know

Answer 4

I know how to plot coordinates, I don't know how to plot equations

Answer 5

I just dont understand the problem

Answer 6

@Pawanyadav Are you still here?

Answer 7

Anyone?

Answer 8

@mathmale Can you help me?

Answer 9

first of all, what are the intergers from -3 to 3, inclusive

Answer 10

-3, -2, -1, 0, 1, 2, and 3 right?

Answer 11

great, now, according to the equation given, what are the y values corresponding to each value you just wrote

Answer 12

39, 19, 7, 3, -1, -13, and -33

Answer 13

fantastic! now plot the following points on a corrdinate plane: (-3,39),(-2,19),(-1,7),(0,3),(1,-1),(2,-13),(3,-33)

Answer 14

ok

Answer 15

Finally, connect all the points in this order

Answer 16

Where do i get a coordinate plane?

Answer 17

nevermind

Answer 18

A coordinate plane is a plane made of the horizontal or x axis, and the vertical or y axis, the intersection is set to be (0,0)

Answer 19

your equation should be -(2x)^2+3, not -2x^2+3 because power take priority over multiplication

Answer 20

I know but where do i find one to wrte on?

Answer 21

just draw one yourself

Answer 22

ok I'm done

Answer 23

It's a straight line going north-west

Answer 24

Hello @caozeyuan ?

Answer 25

it cannt be, you are going to see eith a valley or a hill, 100%

Answer 26

What?

Answer 27

Show me what it is supposed to look like

Answer 28

Hellooooo

Answer 29

Anyone????

Answer 30

I plot it on google, and here it is

Answer 31

oh ok

Answer 32

What about y = 1/3 |x| -2 ?