Mathematics
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OpenStudy (anonymous):
Which of the following equations has the solution x=5
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OpenStudy (aihberkhan):
Just give me the equations and I will help1 :)
@Cruznatalie150
OpenStudy (alexandervonhumboldt2):
(a-b)=0
where b is the solution
OpenStudy (anonymous):
select alll that apply
these are multiple choice answers
OpenStudy (alexandervonhumboldt2):
i dont see the answers
OpenStudy (anonymous):
1. 2^3x=8^3x
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OpenStudy (anonymous):
2. 4^x=4^5x-20
OpenStudy (alexandervonhumboldt2):
just substitute 5 for x in each equation and check which will be correct
OpenStudy (anonymous):
3. 4^x+6=9^x+8
OpenStudy (anonymous):
4. 2^x=6^x-3
OpenStudy (anonymous):
i did but i got stuck on 3
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OpenStudy (anonymous):
this is simplifying radicals
OpenStudy (alexandervonhumboldt2):
4^3==4*4*4=64
OpenStudy (anonymous):
if you could explain to me step by step
OpenStudy (anonymous):
but its just 4^x it dosent have a varriable
OpenStudy (welshfella):
when x = 5, 4^x = 4^5 = 1024
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OpenStudy (welshfella):
4*4*4*4*4 = 4^5
OpenStudy (anonymous):
oh ok so then what would be the answer or how would i solve it @welshfella
OpenStudy (anonymous):
select alll that apply
OpenStudy (welshfella):
for number 2
left side = 4^5 = 1024
right side = 4^(5(5) - 20) = 4^5 = 1024
so?
OpenStudy (anonymous):
@AlexandervonHumboldt2 @welshfella like for is equal to 5 right question 4 i substituted them in divided by 2 both sides
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OpenStudy (anonymous):
beause it asking has a solution to 5
OpenStudy (anonymous):
so then 2 would work
OpenStudy (welshfella):
??
the left side = right side
Therefore x = 5 is a solution to this equation.
OpenStudy (welshfella):
Yes equation 2 has the solution x = 5.
OpenStudy (anonymous):
DOES EQUATION 4 HAVE SOLUTION FOR 5 I THINK IT DOES BUT AM I RIGHT
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OpenStudy (welshfella):
No
LHS = 2^5 = 32
RHS = 6^(5-3) = 6^2 = 36