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integral calculus, power rule Someone please check my work Uploading attachment :)
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the fraction 27/9 can be reduced since both of them are divisible by 9... unless I'm reading that wrong.
yeah I am.. my bad. hold on let me do this in paint.
it's just that I have super bad luck with the letter z and the number 2 right next to each other. I always trip on it.
@UsukiDoll sorry for my sloppy handwriting lol :)
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there's a sign error for \[\huge -az^{\frac{-3}{2}} \] . that exponent should be positive.
oh I see , my bad! Thanks alot!
|dw:1448705597504:dw|
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