Question

Factor completely 50a2b5 - 35a4b3 + 5a3b4

A. 5a2b3(10b2 - 7a2 + ab)
B. 10b2 - 7a2 + ab
C. a2b3(50b2 - 35a2 + 5ab)
D. 5(10a2b5 - 7a4b3 + a3b4)

Answer 1

Will medal

Answer 2

Hey what do you think we do first

Answer 3

What number can go into both 50,35,5?

Answer 4

you there @Puppylover100

Answer 5

5

Answer 6

Ok 5 do you think we can factor anything else out like variables ?

Answer 7

Well there is a^2 b^5 a^4 b^3 a^3 b^4

the two most common numbers are 3 and 4 2 can go into four ut not 5 or 3

Answer 8

so from looking at the answer choices, what do you think th answer is?

Answer 9

D

Answer 10

D??? do you know how to factor?

Answer 11

Why wouldn't be D? If you muliply everything by 5 you would get the original problem

Answer 12

No we have to divide

Answer 13

ok 5 goes into both correct?

So we divide 5 by the 50,35,5

Answer 14

5 goes into 50 ten times, 35 seven times, and 5 once

Answer 15

a and b goes into all 3 terms

so we find the smallest of both A and B so we have

a2 and b3 and we subtract it from all 3 terms

Answer 16

ok

Answer 17

so 50/5=10

so we subtract 2-2=0 5-3=2

Answer 18

so what do we get

Answer 19

10b^2

Answer 20

correct because 2-2=0 so a cancels out :D

how about the next term

Answer 21

7a^2

Answer 22

how about the next

Answer 23

ab

Answer 24

So the answer is?

Answer 25

10b^2-7a^2+ab

Answer 26

you forgot the something in the beginning

Answer 27

5(10b^2-7a^2+ab)

Answer 28

you forgot the variables

Answer 29

5a^2b^3(10b^2-7a^2+ab)

Answer 30

Correct :D

Answer 31

Thank you SO much

Answer 32

Anytime

Answer 33

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Answer 34

:)

Answer 35

Thanks

Answer 36

:D

Answer 37

:D