Question

C++,

https://www.dropbox.com/s/b0m1jvnjg6i3dtr/Screenshot%202015-11-28%2018.24.11.png?dl=0

Answer 1

I think it'd be easy enough if you convert it into a string first. Then the amount of commas you should need is string length/3 and you can work backwards starting at the end of the string and counting in 3s and inserting a comma.

for example
//check if length <3
do nothing
//otherwise
add commas appropriately

Answer 2

but how do I manipulate the string in C++ @bibby

Answer 3

PrintWithCommas (long int x)
{int g=x;
for(int i=0, g>0,i++)
{g=g%10;sumOfDigits=i;}
if sumOfDigits%3==0
{int h= sumOfDigits;
while h!=0
{
cout<<x-(x* power(10,h))<<",";
h=h-3;
}

if sumOfDigits%3==1
{int h= sumOfDigits+2;
while h!=0
{
cout<<x-(x* power(10,h))<<",";
h=h-3;
}
if sumOfDigits%3==2
{int h= sumOfDigits+1;
while h>0
{
cout<<x-(x* power(10,h))<<",";
h=h-3;
}

}

Answer 4

not necessary to manipulate the original string. you can do something like this
```
//count back 3 spaces from the end, insert a comma there,
//keep going in groups of 3 until we've run out the length of the string
int pos=str.length()-3;
string new;
while (pos> 0) {
new.insert(pos, ",");
pos-=3;
}
```

I think you could also do it using a counter. so like count++, if count>3 insert.

let me test this out

Answer 5

but i have little problem with my code, first one i always had " ," at the end of what ever i'm writing lol

Answer 6

I'm sure there's something you can do with iomanip but I'm not too sure what specifically
this way works fine though http://puu.sh/lBSVj/59a89edba7.png

Answer 7

nice!

Answer 8

yes but this is not solved recursively

Answer 9

also the user is going to enter a long integer , not a string

Answer 10

oh, misread it, anyhow you should be able to convert a long to a string without issue
I'm not here to do your assignment for you

Answer 11

this may not be the prettiest, but something like this:

void print_with_comma(long int xx)
{
if (xx<1000)
cout << xx;
else
{
print_with_comma(xx/1000);
cout << "," ;
xx= xx-(xx/1000)*1000;
if (xx<10) cout << "0";
if (xx<100) cout << "0";
cout << xx;
}
}