Question

Help please !!!

Answer 1

@directrix

Answer 2

\[log_3(x-2)+log_3(x-8)=3\]Using the addition rule:\[log_3((x-2)(x-8))=3\]Simplifying:\[log_3(x^2-10x+16)=3\]Removing the log:\[x^2-10x+16=3^3=27\]Rearranging:\[x^2-10x-11=0\]Factoring\[(x-11)(x+1)=0\]Giving us answers of x=11, x=-1. You can't take the log of a negative number, so our only solution is x=11.