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Find solutions for the equation sin^2 x + sin x = 0
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I've gotten to: sin x(sin x + 1) = 0 not sure where to go from here...
set it equal to zero example \[\rm x(y+z)=0~~~\rightarrow ~~x=0~~~~and~~y+z=0\]
okay so sin x = 0 sin x + 1 = 0
right now solve sinx+1=0 for sinx
sin x +1 = 0 sin x = -1
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correct so sinx = 0 and sinx = -1 you can use the unit circle or triangles theorem to find exact solution
so since sine = y I'd have to look at the unit circle for coordinates that have a y of -1 or 0?
correct sin theta =y-coordinate
thank you!
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