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Mathematics 23 Online
OpenStudy (gokuporter):

http://prntscr.com/98gr7s

pooja195 (pooja195):

Use the elmination method

pooja195 (pooja195):

Or substituion whatever u like

OpenStudy (gokuporter):

How do you do the elimination method

pooja195 (pooja195):

Ok let's stick with substituion :P We need to solve equation 1 for x

pooja195 (pooja195):

x+y=5 isolate x

OpenStudy (gokuporter):

Okay

pooja195 (pooja195):

Do you know how?

OpenStudy (mathmale):

Hint: what's the mathematical opposite of addition?

OpenStudy (gokuporter):

Subtractioon

pooja195 (pooja195):

Good subtract y from both sides

pooja195 (pooja195):

You get x=-y+5

pooja195 (pooja195):

Equation 1= x=-y+5 Equation 2= x-2y=2

pooja195 (pooja195):

We know the value of x already so just plug it into equation 2 -y+5-2y=2 solve for y

pooja195 (pooja195):

i need to go so @sleepyjess or @TheSmartOne will take over :)

OpenStudy (gokuporter):

What's the value of x?

OpenStudy (sleepyjess):

Equation 1= x=-y+5

OpenStudy (gokuporter):

Okay, how do I solve it?

OpenStudy (sleepyjess):

substitute that in for x in the second equation

OpenStudy (gokuporter):

How do I do that?

OpenStudy (sleepyjess):

Just put it in instead of x...

OpenStudy (gokuporter):

Y= y-2y=2

OpenStudy (sleepyjess):

-y+5-2y=2

OpenStudy (gokuporter):

Now what?

OpenStudy (sleepyjess):

Solve for y

OpenStudy (sleepyjess):

combine like terms on the left side

OpenStudy (gokuporter):

3y?

OpenStudy (sleepyjess):

-

OpenStudy (gokuporter):

0y

OpenStudy (sleepyjess):

5-3y=2

OpenStudy (gokuporter):

2y?

OpenStudy (gokuporter):

.-.

OpenStudy (sleepyjess):

move the 5 over

OpenStudy (gokuporter):

Over what?

OpenStudy (sleepyjess):

to the other side

OpenStudy (gokuporter):

3y-5=2

OpenStudy (sleepyjess):

5-3y, how do we get the 5 to the right side?

OpenStudy (sleepyjess):

5-3y=2

OpenStudy (gokuporter):

.-. You wrote that before.

OpenStudy (gokuporter):

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