Question

Help? Solve the following system of equations.
x + y = 12
x – y = 6

A.(3, 9)

B.no solution

C.infinite number of solutions

D.(9, 3)

Answer 1

So we have 2 equations
x+y=12 <---equation 1
x-y=6 <----equation 2
I know the substitution method well enough to teach it to you so lets stick with that :))
Lets start by isolating a variable equation 1 has a variable alone lets isolate it
x+y=12 <----equation 1
Subtract y from both sides
x=-y+12
Now we have
x=-y+12 <---equation 1
x-y=6<---equation 2
Now we know the value of x let's plug equation #1 into equation #2
\[\huge~\rm~ -y+12-y=6\]Solve for y tell me what you get :)

Answer 2

Is it C?

Answer 3

No

Answer 4

I need help :/ I'm in 8th grade and math is hard.

Answer 5

Im a person who helps people who are willing to learn i guess we are both stuck

Answer 6

Well can you give me a hint?

Answer 7

−y+12−y=6
Combine like terms

-y-y=?
basically saying
-1-1=?

Answer 8

No solution??

Answer 9

No -.-

Answer 10

Don't yell at me!

Answer 11

o.O i yelled at you?

Answer 12

No he did. Whoever that person is

Answer 13

Ok -1-1=?

Answer 14

-2?

Answer 15

yes -1-1=-2

Answer 16

Okay!

Answer 17

Good
−y+12−y=6
-2y+12=6
now we subtract 12 from both sides
6-12=?

Answer 18

-6

Answer 19

yes

Answer 20

Good
-2y=-6
divide both sides by -2
-2/-2=1
so just y
-6/-2=?

Answer 21

-8

Answer 22

We're dividing not adding

Answer 23

-6 divided by -2 =?

Answer 24

3

Answer 25

Good so y=3
only one of your options has y as 3 what is the answer?

Answer 26

I would go with A

Answer 27

Nope
(x,y)
y=3
(x,3)

Answer 28

Try again

Answer 29

I got it! Thanks!

Answer 30

What did you get?