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1-cos(12x) 2cos^2(12x) 2sin^2(12x) 2cos^2(6x) 2sin^2(6x)
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the first one is the question and others are options? or there are 5 questions? :3
\(\Large 1-\cos 2A = 2 \sin^2 A\) use that :)
here, 2A = 12x
Cutie: your question is crying out for clarification. What do the instructions for this problem say?
yes the first one is the question!! sorry for such a broad question. @mathmale @hartnn
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2sin^2(6x)
yep, thats correct :)
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