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@pooja195
@Anaise
8>5-3q>-13 What we're going to do is like solving for q (meaning we isolate q). 8 > 5-3q > -13 8-5 > 5-5-3q > -13-5 3 > -3q > -18 So far so good ?
Hmm seems you're not here. What we do now is multiply by -1/3 to get rid of the -3 near q. When we multiply an inequality by a negative number, we reverse the inequality symbol. Hence we get 3 > -3q > -18 3*(-1/3) < -3q*(-1/3) < -18*(-1/3) -1 < q < 6 The solution interval would be S= ]-1,6[
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