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(fog) f(g(x)) f (x) =x^2-3 f squares whatever is in its arms (x) and then subtracts 3. g(x)=2x+1 g doubles whatever is in its arms and adds 1
f ( g(x) = f ( 2x+1 ) = ( 2x + 1) ² - 3 f squares whatever is in its arms (x) and then subtracts 3.
f ( g(x) = f ( 2x+1 ) = ( 2x + 1) ² - 3 We have to crank out this: ( 2x + 1) ² - 3 See what you get, okay?
yea
4x^2 + 4x -2
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Yes, f (g(x) = 4x² + 4x - 2
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