thanks
The equation of the line with slope 2/3 and passing through (6,2) is y = (2/3)* x - 2 This comes from the online calculator at http://www.webmath.com/equline2.html Instructions are there also.
@cutegirl Test Options: Option 1: a (3,0) Check the options in this way: y = (2/3)* ( 3 ) - 2 ---> Solve for y. If you get 0, then the point (3,0) is on the line. If you do not, then the point (3,0) is not on the line. Post what you get, okay?
i got zero
Sorry, I did not see that.
y = (2/3)* ( 3 ) - 2 = 2-2 = 0
its all good
What about this: y = (2/3)* ( -3 ) - 2 ---> Solve for y.
-4
So ( -3, -4) is on the line also.
how about a or b?
Option A is the first one you tested.
What about c. (3,-2) y = (2/3)* ( 3 ) - 2 ---> Solve for y. If you get -2 for y, then the poiont (3,-2) is on the line. So crank out (2/3)* ( 3 ) - 2
its zero
thanks a brunch
bunch
Did you decide on A and D, then? You are welcome.
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