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Mathematics 17 Online
OpenStudy (hijacktrolo):

i give medals

OpenStudy (hijacktrolo):

Which relationship is always true for the angles r, x, y, and z of triangle ABC? x + z = y 180 degrees − x = r x + y + z = 180 degrees x + y + z = 90 degrees

OpenStudy (baru):

sum of angles in a triangle = ?

OpenStudy (baru):

sum of angles on a straight line = ?

OpenStudy (hijacktrolo):

??????????

OpenStudy (baru):

do you know the answers to my questions?

OpenStudy (baru):

it's what you'll need to solve the question you posted

OpenStudy (hijacktrolo):

straight line is 90?

OpenStudy (baru):

no

OpenStudy (hijacktrolo):

180 :D

OpenStudy (hijacktrolo):

it should all equal 180 :)

OpenStudy (baru):

ok, so which of the angles x,y,z,r lie on a straight line?

OpenStudy (hijacktrolo):

x?

OpenStudy (baru):

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OpenStudy (baru):

L and M are angles that lie on a straight line

OpenStudy (hijacktrolo):

ok

OpenStudy (baru):

similarly, there are angles lying on a straight line in your figure. can you recognize them?

OpenStudy (hijacktrolo):

x and r lie on a straight line

OpenStudy (baru):

exactly!! :D

OpenStudy (hijacktrolo):

so its b

OpenStudy (baru):

why do you say its b?

OpenStudy (hijacktrolo):

i dont know i think it just makes sense somehow but dont know why :(

OpenStudy (baru):

angles on a straight line add up to 180 so x+r=180 do you understand this?

OpenStudy (hijacktrolo):

ohhhhhhh yeah i do

OpenStudy (hijacktrolo):

so its c because x+y+z=90 so then with the addition of r you get 180

OpenStudy (baru):

ok now we do a little algebra look at option b 180 - x= r

OpenStudy (baru):

add x to both sides of the equation, what do you get?

OpenStudy (hijacktrolo):

90?

OpenStudy (baru):

add 'x' to both sides

OpenStudy (hijacktrolo):

oh 180

OpenStudy (baru):

:/ you haven't understood algebra

OpenStudy (hijacktrolo):

i still say it is c

OpenStudy (baru):

I wish I could say "go with your gut feeling" but math dosen't work this way. you will have to pay attention and learn algebra at some point. its not very hard, good luck :)

OpenStudy (hijacktrolo):

thanks

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