Question

The force of repulsion between two like-charged table tennis balls is 8.2 * 10È¥ newtons. If the charge on the two objects is 6.7 * 10È© coulombs each, what is the distance between the two charges? (k = 9.0 * 10© newton·metersÆ/coulombÆ)

Answer 1

Try using this:
\[\huge \text{F}=k\frac{q_1q_2}{r^2}\]

Answer 2

Solve for \(r\)

Answer 3

thanks. im also confused about this one