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The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle. If l = length and w = width, which of the following systems could be used to solve the problem? A. l = 3w + 2 and 2l + 2w = 100 B. l = 2w + 3 and 2l + 2w = 100 C. l + 2 = 3w and 2l + 2w = 100 I think its C but I'm not sure..
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If you understand the problem carefully you will see that you are wrong
It says 2 more than 3 times the width=lenght so in short words 3w+2=L
are you there brooke
Yeah i am..so the answer is A.
yes
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You are CORRECT!!!
Okay cool, thanks for helping me out.
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