Question

is -1+9t^2 a difference of squares ?

Answer 1

-1+9t^2=9t^2-1

a^2-b^2=(a-b)*(a+b)

9t^2-1=(3^2)(t^2)-1^2

Answer 2

thus it is.......?

Answer 3

in your case a=9t^2 and b=1

Answer 4

It just asks for a yes or no answers

Answer 5

what do you think?

Answer 6

no.

Answer 7

swap the `-1` and `9t^2` to get `9t^2 - 1`

the 9t^2 can be written as (3t)^2