Question

@Michele_Liano

Answer 1

please, where is the question?

Answer 2

y=1/3|x|- 2

Answer 3

here we have to distinguish the subsequent cases:
\[\huge \frac{1}{3}\left| x \right| - 2 = \begin{array}{*{20}{c}}
{\frac{1}{3}x - 2,\quad if\;x \geqslant 0} \\
{ - \frac{1}{3}x - 2,\quad if\;x < 0}
\end{array}\]

Answer 4

hint:
the line represented by the equation \(y=(1/3)\;x-2\) passes at point \((0,-2)\), furthermore, also the line \(y=-(1/3)\;x-2\) passes at point \((0,-2)\)