Question

cotx = -2 and secx < 0
How do I find sinx, cosx, and tanx?

Answer 1

r u given any more info?

Answer 2

so you know that

cot x = cos x / sin x
and
tan x = 1/cot x

yes ? hope this will help you

Answer 3

Given :- Cotx = -2
secx<0
Approach:- We know cotx and secx are both together negative in only 2nd quadrant
Solution :- cotx =-2 so, tanx = -1/2 (cotx = 1/tanx)
sinx = \[1/\sqrt{5}\]( sinx is positive in second quadrant)
cos= \[-2/\sqrt{5}\] (cos x is negative in seond quadrent )