Question

Three consecutive odd integers have a sum of
21. Find the integers. :( pleaseee

Answer 1

Okay.

he meaning of consecutive means continuous {please don't be offended }
so let the first term be 'y', the second one be 'y+1' and the third one be 'y+2'
so according to the question,
y+(y+1)+(y+2)=21
you don't need to worry as there is a '+' sign outside the bracket you just need to add
= y+y+1+y+2=21
group the like terms [terms with same ending like 'y']
= y+y+y+1+2 =21
3y+3=21
{just to tell you y*y*y= y³ }
now 3y=21-3
3y=18
y=18/3
y=6
so the integers are y=6,
y+1=6+1=7 and
y+2= 6+2=8

if you want to check=6+7=13+8=21
hence proved

Answer 2

Hope this helped! Have a great day!

Also a medal would be much appreciated! Just click best response next to my answer. Thank You!

@ElisaNeedsHelp

Answer 3

Ofc the medal :D lol