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Factor 3c^3 + 375. 3(c + 5)(c2 – 5c + 25) (c + 5)(c2 – 5c + 25) (c – 5)(c2 – 5c + 25) –3(c + 5)(c2 – 5c + 25)
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@Directrix
Factor out the common 3. 3c^3 + 375 = 3* (c^3 + 125) Then, you will need to factor the sum of the cubes of c^3 + 125.
Attached is the pattern for factoring the sum of two cubes. @18jonea
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