Question

(2x-1)^2 = 49
Solve quadratic function with square roots

Answer 1

first subtract 49 from both sides:

(2x-1)^2-49=0

now use difference of squares:
a^2-b^2=(a-b)*(a+b)
a=2x-1
b=7

(2x-1-7)*(2x-1+7)=0
to find roots you need to equal ( ) to 0:

2x-7-7=0
2x-1+7=0

solve each eqaution

Answer 2

So I'll have two answers?

Answer 3

Take square root both side
So 2x-1=+7 also 2x-1=-7
As roots of 49 are both +7 and-7
So u will get 2 answer