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Simplify: sin B + (cos2B/ Sin B)
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is that a `cos^2(B)` or `cos(2B)`?
Simplify: sin B + (cos^2 B/ Sin B)
factor out 1/sin B from both terms
I don't understand how to
[ noting that the first term `sin B` is equal to `sin^2 B / sin B` ]
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sin B + ( cos^2 B / sin B ) = sin^2 B / sin B + ( cos^2 B / sin B ) = 1 / sin B ( .... + .... ) = @Ambbiiee
2 sin b/2 (cos b/2 + sin b/2 )=0
what? how
Let me redo it
ok
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