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-7-2x^2= -45 Solve quadratic function with square roots
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i am noy sure but ... -7-2x^2=-45 -7-2x^2+45=0 -2x^2+32=0 -2(x^2-16)=0 -2(x^2-16)/2=0/2 x2-16=0 (x+4)(x-4)=0 x=4,-4
Not sure? Try your answer in the original formula, and see if it works! \[-7-2x^2=-45\]we think \(x=4\) might be a solution, so let's try it. \[-7-2(4)^2=-45\]\[-7-2*16 = -45\]\[-7-32=-45\]\[-39=-45\]apparently that's not the solution.
okey((try you
so what would the answers be?
-2x^2=-45+7 -2x2=-38 Divided by -2 x2=19 So x=√(19) and -√(19)
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Got it...
yes thank you!
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