Question

Medal for best answer!!!




A company dyes two sizes of rugs. A small rug requires 2 hours for dyeing and a medium-size rug requires 3 hours for dyeing. The dyers need to make at least 15 rugs, and they must do it in less than 60 hours. Let x equal small rugs and y equal medium rugs. Which of the following inequalities can be paired with x + y ≥ 15 to create a system that represents this situation?




2x + 3y < 60

3x + 2y < 60

2x + 3y > 60

3x + 2y > 60

Answer 1

start with one small and one medium, then keep adding one to each side. is that confusing?

Answer 2

I dont' get how to do it If you can show me how

Answer 3

so


small-2hr
med-3hr

Answer 4

how many smalls can u do in one hour?

Answer 5

It takes 2 hours for small rug for dyeing.

Answer 6

o.... :/

Answer 7

well, how many in 60 hours

Answer 8

what im trying to do is get ur brain working with these equations
think of the question like this

s*x+m*x+=less than or equal to 60

Answer 9

It will be like 50

Answer 10

well, less than that

Answer 11

but look at this, smalls and mediums can be s and m
and we need to find numbers to substitute so that when we add them, you have somthing less than or equal to 60

Answer 12

Can you show me how I wont be able to do it

Answer 13

start with a:: 2x + 3y < 60. substitute x with 2 and y with three

Answer 14

I ended up with 13<60

Answer 15

thats true. so it could be a. but lets work b 3x + 2y < 60. make it look like 3*2+2*3<60 then work

Answer 16

12<60

Answer 17

2x + 3y > 60

2*2+3*3>60?

Answer 18

So the right choice is the 1st one?

Answer 19

you tell me. d might could be the right answer.

Answer 20

3x + 2y > 60

3*2+2*3>60

Answer 21

it could be a or b

Answer 22

They both end up to be true idk

Answer 23

are you looking at the second part of the question? Which of the following inequalities can be paired with x + y ≥ 15 to create a system that represents this situation?

Answer 24

How can I pair them up?

Answer 25

wich is closer to 15?

Answer 26

The first one it was 13<60 and the other one was 12<60

Answer 27

So its A?

Answer 28

that would be my answer.

Answer 29

Okay thanks

Answer 30

no problem

Answer 31

anything else?

Answer 32

Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the graph of the following inequality:

y > one half x + 2


The origin is not included in the shaded region and the shaded area is above the line.

The origin is not included in the shaded region and the shaded area is below the line.

The origin is included in the shaded region and the shaded area is above the line.

The origin is included in the shaded region and the shaded area is below the line.

Answer 33

I know it either A or C but now sure which one

Answer 34

i need the graph pic if there is one

Answer 35

There isnt just the equation

Answer 36

weird

Answer 37

but it says shaded area

Answer 38

http://www.mathpapa.com/algebra-calculator.html

Answer 39

I used this site to help me graph the equation

Answer 40

Just graph it there and change the one/half to 1/2

Answer 41

o ok

Answer 42

its a

Answer 43

Okay can u help me with last one I have like 10 mins left until I have to go

Answer 44

The graph below shows the solution to a system of inequalities:

Answer 45

Which of the following inequalities is modeled by the graph?



2x + 5y ≥ 14; x ≥ 0

2x + 5y ≤ 14; x ≥ 0

2x − 5y ≤ 14; x ≥ 0

−2x − 5y ≤ 14; x ≥ 0

Answer 46

It is either A or B

Answer 47

i dont know. it a confusing question

Answer 48

I used the graph site I showed you and it is the same exact thing with the A and B if you dont know it its okay

Answer 49

@whpalmer4 can u help me?

Answer 50

its b

Answer 51

is that a guess or your sure?

Answer 52

im sure. checked it three times

Answer 53

Okay thanks alot

Answer 54

can i get medal for that one?

Answer 55

How can I give another medal I dont know how to do that

Answer 56

click the medal to the right of my reply

Answer 57

I can't press anything there because i already gave one

Answer 58

its ok. i dont really need it

Answer 59

If you want it tell me how to

Answer 60

its fine

Answer 61

Okay thanks again

Answer 62

no problem is u need anythin pm me

Answer 63

if*