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Mathematics 19 Online
Hayhayz (hayhayz):

Which equation represents the vertical asymptote of the graph? http://prntscr.com/9acofx

Hayhayz (hayhayz):

@malcolmmcswain

OpenStudy (malcolmmcswain):

I can't see it, can you upload it as an attachment?

Hayhayz (hayhayz):

alright hold on

Hayhayz (hayhayz):

OpenStudy (malcolmmcswain):

Ok, so do you know what an asymptote is?

Hayhayz (hayhayz):

imaginary line on a graph that a function or equation approaches more and more closely

OpenStudy (malcolmmcswain):

Correct. So, what is your guess?

Hayhayz (hayhayz):

0?

OpenStudy (malcolmmcswain):

Ok, do you know how to find limits?

Hayhayz (hayhayz):

choices= x=-8 y=-8 x=0 y=0

Hayhayz (hayhayz):

no

OpenStudy (malcolmmcswain):

What is the limit as x approaches 8 from the negative side?

Hayhayz (hayhayz):

umm how do find a limit?

OpenStudy (malcolmmcswain):

In other words, what value does it seem to be approaching?

OpenStudy (malcolmmcswain):

So, as x gets closer and closer to 8, y gets higher and higher, right? So, our limit is infinity :)

Hayhayz (hayhayz):

oooh okay

OpenStudy (malcolmmcswain):

Ok, but wait.

OpenStudy (malcolmmcswain):

So, using that, we can deduce what?

OpenStudy (malcolmmcswain):

Also, I made a mistake. x is approaching -8

OpenStudy (malcolmmcswain):

So, the answer is...

OpenStudy (malcolmmcswain):

when y = infinity, -insert answer-

Hayhayz (hayhayz):

wait so how does the limit help find the vertical asymptotes? cuz in my lesson it says the location of a vertical asymptote is found by setting the denominator of a simplified function equal to 0 solving for x but since theres no equation thats why im confused and i have no idea lol

OpenStudy (malcolmmcswain):

That's another way to do it, but I find limits easier.

Hayhayz (hayhayz):

so x=-8?

OpenStudy (malcolmmcswain):

Correct :)

Hayhayz (hayhayz):

Thank you mal :)

OpenStudy (malcolmmcswain):

And the horizontal asymptote would be...?

OpenStudy (malcolmmcswain):

No problem :D

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