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one number is 10 more than another number.Form a quadratic function that will allow you to find the minimum product of the two numbers. find the numbers and the minimum product.
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@jim_thompson5910
so far x=10+y how to make it into quadratic equation
@mathmale
@calculusxy any idea
Let \(x\) be the first number. Then the second number is \(x+10\). The product of the two is \(x(x+10)=x^2+10x\). To find the minimum of the product, you can complete the square to write this quadratic in vertex form \((x-a)^2+b\), which will be minimized when \(x=a\) since that makes the first term disappear, leaving you with \(b\).
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o wow
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