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The equations of two adjacent sides of a rhombus are: y = 2x +4 , and y = -(1/3)x + 4 If 12,0 is one vertex and all vertices have positive coordinates, find the coordinates of the other 3 vertices. I figured out that one of the other vertices is 0,4 but I'm stuck on finding the other two, any hints would be appreciated! Thanks in advance!
I lost my Geometry notebook e-e
isnt a rhombus a squashed square?
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