Question

Heelp

A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey results for the first-, second-, and third-period classes are as follows:

First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0

Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3

Which is the best measure of center for second period and why?

Mean, because there are no outliers that affect the center
Median, because there is 1 outlier that affects the center
Interquartile

Answer 1

@ganeshie8 @dan815 @Michele_Laino @pooja195 @Luigi0210 @ganeshie8 @nincompoop @AlexandervonHumboldt2

Answer 2

I think that we have to compute the mean value of the values of the second period

Answer 3

I'm really lost and I really need an A on this please help mer

Answer 4

Mean, because there are no outliers that affect the center
Median, because there is 1 outlier that affects the center
Interquartile range, because there is 1 outlier that affects the center
Standard deviation, because there are no outliers that affect the center

Answer 5

Those are the answers

Answer 6

when I was at university, at first laboratory physics course, usually, I neglected the outliers, and subsequently I computed the mean value, namely after deleting or rejecting all outliers.
Nevertheless, please ask to another helper

Answer 7

So you don't know the answer?

Answer 8

Statistucs is not my forte by I would say the mean is best measure of center

Answer 9

So which option do you suggest?

Answer 10

3