A local hamburger shop sold a combined total of
601 hamburgers and cheeseburgers on Friday. There were 51 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Friday?

Question

A local hamburger shop sold a combined total of 
601 hamburgers and cheeseburgers on Friday. There were 51 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Friday?

atsie · Answer

What is 601 - 51?

anonymous · Answer

550? But it's not that simple is it.

atsie · Answer

I'm pretty sure it is.

nathalie0918 · Answer

actually it is 275 because it says that there were 51 MORE cheese sold than hamburgers  so first you take away 51 from 601= 550 
the you divide 550 by 2 which is 225 for the hamburgers
and for the cheese you add 225 + 51 = 276 
and 276+225=501

atsie · Answer

@nathalie0918 Your right. I misguided her. Sorry about that

nathalie0918 · Answer

its alright @Atsie, at lease you tried to help that is all that counts :)

atsie · Answer

@nathalie0918 I just remember being taught word problems like these differently and got mixed up. Thanks for the comfort though :)

retireed · Answer

I believe nathalie0928 made a math error

H = Hamburger  CB = Cheeseburger   TOTAL = the number of burgers sold = 601
51 more CB were sold than H

Two unknowns so you need two equations!

1)  H + CB = 601
2)  CB - H  = 51

Add these equations and H will be eliminated.

3)  2CB = 652   Divide both sides by 2

4)    CB = 326      It is easy to solve H by modifying eq 2)