Question

need help
here is the solution of c++ string manipulation

Answer 1

#include <iostream.h>
#include <string.h>
using namespace std;
void uppercaseString(char *s){
while( (*s = toupper(*s)) ) ++s;
}
main()
{
char *a=new char[40];
char *b=new char[40];
char *c=new char[40];
char *d=new char[40];
char e[80];
char s[80] = "a,b";


cout <<"Enter string 1 : ";
cin >> a;

cout <<"Enter string 2 : ";
cin >> b;
//length of strings

cout<< "The length of string 1 is : " <<strlen(a) << endl;

cout<< "The length of string 2 is : " <<strlen(b) << endl;

//upper case

uppercaseString(a);

cout << "String 1 in upper case: " << a << endl;
uppercaseString(b);
cout << "String 2 in upper case: " << b << endl;

if(strcmp(a,b)==0)
{
cout<<"Both strings are the same \n";
}
else
{
cout<<"Both strings are different \n";
}


//concatenation of strings
strcat(e,a);
strcat(e,b);
cout<< "Both strings after concatenation: " << e << endl;
}

Answer 2

plz look in the screen shot that after concatenation : \[L \pm Openstudy\]
why it is \[L \pm \] ?