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how do I solve 3x+-4=x+4
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do you mean ?\[3x\pm4=x+4 \]
yes
Firstly you need to reorder everything -4 + 3x = x + 4 and -4 + 3x = 4 + x
do it for two case : 1 3x+4=x+4 2 3x-4=x+4
then solve for the variable x by move all your terms containing x to the left, and all other terms to the right.
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so it should look like this... \[-4 + 3x + -1x = 4 + x + -1x\]
is a step to solving for x
−4+3x+(−1x)=4+x+(−1x) ? if you mean it ,you'r right
@djHunter You following all this?
let me see your work
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