Question

(2/3)^-2

Answer 1

hint:
\[a^{-b}=\frac{ 1 }{a^b }\]

Answer 2

I'm having a blonde moment..

Answer 3

so it would be
\[(2/3)^{-2}=\frac{ 1 }{ (\frac{ 2 }{ 3 })^2 }=?\]

Answer 4

okay..so, \[\frac{ 1 }{ \frac{ 2 }{ 3^{} }^{2} }^{}\]

Answer 5

yeah

now (2/3)^2=4/9

so we have:
\[\frac{ 1 }{ 4/9 }=1*9/4=?\]

Answer 6

9/4

Answer 7

yay :)

Answer 8

yah!

Answer 9

Thanks! You're a lot of help!:)

Answer 10

:)