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Eliminate the parameter to find a Cartesian equation of the curve.
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\[x=\sin \frac{ 1 }{ 2 }\theta\] \[y=\cos \frac{ 1 }{ 2 }\theta\] in −π ≤ θ ≤ π
square and add.
@random231 do u know what −π ≤ θ ≤ π looks like on a graph?
for (b) Sketch the curve and indicate with an arrow the direction in which the curve is traced as the parameter increases.
−π ≤ θ ≤ π is not a curve @Zenmo its a condition
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what does the condition look like then?
actually, what does a negative unit circle look like?
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