Question

Solve algebraically:

y=x^2-20
y=x-8

I have tried this many times and I can't figure it out.

Answer 1

Plug value of y from eq 1 to equation 2,
We get x^2-20=x-8
x^2-x-20+8=0
x^2-x-12=0
x^2-4x+3x-12=0
x(x-4)+3(x-4)=0
(x-4)(x+3)=0
Can you solve now.

Answer 2

@Supernova_Sonntag

Answer 3

it is 4

Answer 4

4 and -3.(both)

Answer 5

Yes that is all I needed, thank you. I guess I was getting hung up on the factoring.

Answer 6

You are welcome