Question

algebra

Answer 1

use this formula\[y=mx+c\]where\[y=vertical~axis\]\[x=horizontal~axis\]\[m=slope/gradient\]\[c=y-intercept\]

Answer 2

\[To~find~m\]\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]\[First~point(1,1)=(x_1,y_1)\]\[Second~point(7,4)=(x_2,y_2)\]substitute this value into that formula

Answer 3

\[m=\frac{ 4-1 }{ 7-1 }\]\[m=\frac{ 3 }{ 7 }\]

Answer 4

slope is 1/2

Answer 5

sorry,typo...
yup slope is 1/2

Answer 6

thats what i though =)

Answer 7

i got it

Answer 8

In the slope-intercept form of a straight line, I have y, m, x, and c. So the only thing I don't have so far is a value for is c (which gives me the y-intercept). Then all I need to do is plug in what they gave me for the slope and the x and y from this particular point, and then solve for c:

Answer 9

\[y=mx+c\]i randomly choose the first point\[(1,1)~as~(x,y)\]\[m=\frac{ 1 }{ 2 }\]substitute this value into that formula\[(1)=\frac{ 1 }{ 2 }(1)+c\]\[c=\frac{ 1 }{ 2 }\]

Answer 10

Did you get y = 1/2 x + 1/2 or something else? @MARC_

Answer 11

yep i get that eqn

Answer 12

:)