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-x+1, x<0}= -2, x=0}=f(x) x^2-, x>0}= a f(4)=7 b f(-1)=0 c f(1)=0 d f(-2)=0
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So \(f(x) = \begin{cases}-x+1,&x<0\\-2,&x=0\\x^2,&x>0\end{cases}\) , right?
yes
werid, nothing is right to me
you can pick more than 1
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