Question

Can somebody help me with Graphs? I need 5 of my Practice Problems checked. I will medal :3

Answer 1

I have no idea which one it is, Please show me how I can check?

Answer 2

An X value less than 0 is basically a negative number, right?

So what you would do is go to the left side of the graph (Which is the negative side of the graph) and look for all points that lay on that side

Answer 3

So it is C. c, d, j ?

Answer 4

^ Perfect

Answer 5

Awesome! Thank you so much :)
Can you please help me with some more similar to this?

Answer 6

Sure, I don't mind

Answer 7

I think this one is D.

Answer 8

Yes, it is D. Good one!

Answer 9

Awesome cx

I think it's A.

Answer 10

For this one, remember you have to do the X value first and then the Y value (The run over rise method)

Answer 11

For the x value I see that it could be B.point B?

Answer 12

Point B is (2, -4), not (-2, 4). It's (2, 4) because the first value is x and the second is y. You went to the right two, which is positive instead of left two, which is negative. Same with the 4. When finding the Y value, being above 0 is positive (going up) and being below 0 in negative (going down)

Hope that makes sense

Answer 13

It's C! (-2,4)

Answer 14

Right? @FortyTheRapper

Answer 15

Yes! Did the X value first then the Y, good job!

Answer 16

C? @FortyTheRapper

Answer 17

Nice answer!

Answer 18

D?

Answer 19

This is the last one. @FortyTheRapper

Answer 20

Almost
This one is quadrant placing. The first quadrant starts in the upper-right, as you got correct. But instead, you counted clockwise.

You have to count counter-clockwise when counting quadrants

Answer 21

B?

Answer 22

Yep, that's correct =]

Answer 23

Awesome! Than you so much. :)

Answer 24

thank*

Answer 25

Anytime!