Question

Find sec x if tan^2 x= 1/2.

Please no direct answers :)
http://imgur.com/nw3ZgKX

Answer 1

I keep getting \[\sqrt{\frac{3}{2}}\] :/ I don't know what I'm doing wrong.

Answer 2

\[\sec ^2x-\tan ^2x=1,\sec ^2x=1+\tan ^2x=1+\frac{ 1 }{ 2 }=\frac{ 3 }{ 2 }=\frac{ 3*2 }{ 2*2 }=\frac{ 6 }{ 4 }\]
\[\sec x=\pm \frac{ \sqrt{6} }{ 2 }\]

Answer 3

Oh. Thank you :)

Answer 4

yw