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Mathematics 20 Online
OpenStudy (anonymous):

Solve: log(x+9)=2

OpenStudy (anonymous):

\[\log(x)=y\iff 10^y=x\] you should be able to shirt back and forth quickly

OpenStudy (anonymous):

for example \[\log(1000)=3\iff 10^3=1000\]

OpenStudy (anonymous):

*shift

OpenStudy (anonymous):

\[\log(.0001)=-4\iff 10^{-4}=.0001\]

OpenStudy (anonymous):

\[\log(\text{whatever})=2\iff 10^2=\text{whatever}\]

OpenStudy (anonymous):

So it would be 10^(x+9)=2?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

you have i backwards

OpenStudy (anonymous):

\[\log(\heartsuit)=\spadesuit=\iff 10^{\spadesuit}=\heartsuit\]

OpenStudy (anonymous):

No it would be 10^2=x+9?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ok so then the answer would be 91?

OpenStudy (anonymous):

I get it now! Thank you, your a lifesaver!

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