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Solve: log(x+9)=2
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\[\log(x)=y\iff 10^y=x\] you should be able to shirt back and forth quickly
for example \[\log(1000)=3\iff 10^3=1000\]
*shift
\[\log(.0001)=-4\iff 10^{-4}=.0001\]
\[\log(\text{whatever})=2\iff 10^2=\text{whatever}\]
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So it would be 10^(x+9)=2?
no
you have i backwards
\[\log(\heartsuit)=\spadesuit=\iff 10^{\spadesuit}=\heartsuit\]
No it would be 10^2=x+9?
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yes
Ok so then the answer would be 91?
I get it now! Thank you, your a lifesaver!
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