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\(\large\color{#000000 }{ \displaystyle s(t)=\ln(t) }\) \(\large\color{#000000 }{ \displaystyle s(1) =\ln(1)=0 }\) \(\large\color{#000000 }{ \displaystyle s(e) =\ln(e)=1 }\) \(\large\color{#000000 }{ \displaystyle {\rm Slope}=\frac{s(e)-s(1)}{e-1}= }\)
(no calculus needed, just the average rate of change)
ohh ok so I got 1/e-1
Thanks!!
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