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high!!!
@Vincent-Lyon.Fr
@IrishBoy123
@Michele_Laino
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\(I_o * 0.8 * 0.98\)
\(I=I_o\times 0.8\times 0.98\times 0.8=0.63\;I_o\) First you cross a boundary, then you have absorption within the plastic plate, then you cross another boundary to exit into air again.
the intensity reduces by 20% when it incident on plastic from air..but does the intensity reduces by same amount when light comes out to air again?
Yes, those factors are symmetrical: \(T=\left ( \dfrac{n_1-n_2}{n_1+n_2}\right )^2\)
is the reflection coefficient (air to plastic) is same as that when light comes out to air from plastic?
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