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HELP MEDAL AND FAN LELELELEL
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\[2x ^{3}\le98x\]
Ayye lmao its u again :P
Aight so. Here is what I did
\[2x^3 \le 98x \rightarrow 2x^2 \le 98 \rightarrow x^2 \le 49 \rightarrow x \le \pm 7\]
You would be absolutely correct Great job! ^_^
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so wouldnt that simplify out to \[x \le 7 / x \ge -7\]
thats the thing, Idk what im doing wrong but the answer key says this:
Is there a problem here?
\[\left\{ x |x \le-7 \cup 0 \le x \le 7 \right\}\]
Please use appropriate language please. @omgmrduck Or else i'm going to have to report you. Do you understand?
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Is it x is greater than or equal to 7 OR x is greater than or equal to -7?
To be honest, I'm not certain on how they got their solution What's your thoughts, @Vickyisthesmartone123
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