Question

Write down the iterated integral which expresses the surface area of z=y^5cos^2(x) over the triangle with vertices (-1,1), (1,1), (0,2):

Answer 1

I've already found the bounds just need help with H(x,y)
I know \[q(x,y)= y ^{5}\cos ^{2} x\] , has to be written \[h(x,y)= q ^{2}_{x} +q ^{2}_{y} +1\] just need help on getting there

Answer 2

What exactly are you using for your bounds? How are you parameterizing the surface?