Ask your own question, for FREE!
Physics 17 Online
OpenStudy (anonymous):

A proton travels at right angles through a magnetic field of 0.025 teslas. If the magnitude of the magnetic force on the proton is 1.8 × 10-14 newtons, what is the velocity of the proton? The value of q = 1.6 × 10-19 coulombs. A. 1.8 × 105 meters/second B. 1.8 × 106 meters/second C. 2.5 × 106 meters/second D. 3.8 × 106 meters/second E. 4.5 × 106 meters/ second

OpenStudy (souvik):

use Lorentz force \[F _{mag}=q( v \times B)\] since the proton travels perpendicular to the magnetic field \[F _{mag}=q v B\] calculate \(v\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!