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Find the sum that is given by
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...by what?
\[\sum_{k=1}^{5} 3k-1\]
The sum is 40.
I plugged it into the Calculator thank you for your help! :)
The summation you put up basically says: for 5 multiples of 3, subtract 1 from each then add up all of it. So fro that, we get 3 + 6 + 9 + 12 + 15 from sigma 3k. But we need sigma 3k less 1, so we do 2 + 5 + 8 + 11 + 14 which happens to equate to 40.
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