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Ivan drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When Ivan drove home, there was no traffic and the trip only took 5 hours. If his average rate was 21 miles per hour faster on the trip home, how far away does Ivan live from the mountains?
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I believe it would be 105 mi
let onward speed = x mph, then distance = 7x return speed = (x+18) mph, (same) distance = 5(x+18) equating the two, 7x = 5(x+18) 2x = 90 ==> x = 45 mph so distance = 7*45 = 315 miles
its 315 miles!
no that was wrong its 280
how did you get 280??
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