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I'm going to work out an integral I'd appreciate someone check my answer.
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\[\int\limits(\frac{1}{z^{2}}+A)^{2}dz\rightarrow \int\limits(z^{-2}+A)^{2}dz\]
\[\int(z^{-2}+A)(z^{-2}+A)dz\rightarrow \int (z^{-4}+2Az^{-2}Az)dz\]
\[\frac{-z^{-3}}{3}-2Az^{-2}+Az+C\]
\[(a+b)^2 = a^2+2ab+\color{red}{b^2}\]
the second one is-1 no -2
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oh damn I forgot about that
\[\int\limits (\frac{1}{z^4}+2\frac{A}{z^2}+A^2)dz\]
\[\frac{-z^{-3}}{3}-2Az^{-1}+A^{2}z+C\]
yup!
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