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Mathematics 14 Online
OpenStudy (kkutie7):

I'm going to work out an integral I'd appreciate someone check my answer.

OpenStudy (kkutie7):

\[\int\limits(\frac{1}{z^{2}}+A)^{2}dz\rightarrow \int\limits(z^{-2}+A)^{2}dz\]

OpenStudy (kkutie7):

\[\int(z^{-2}+A)(z^{-2}+A)dz\rightarrow \int (z^{-4}+2Az^{-2}Az)dz\]

OpenStudy (kkutie7):

\[\frac{-z^{-3}}{3}-2Az^{-2}+Az+C\]

ganeshie8 (ganeshie8):

\[(a+b)^2 = a^2+2ab+\color{red}{b^2}\]

OpenStudy (kkutie7):

the second one is-1 no -2

OpenStudy (kkutie7):

oh damn I forgot about that

OpenStudy (anonymous):

\[\int\limits (\frac{1}{z^4}+2\frac{A}{z^2}+A^2)dz\]

OpenStudy (kkutie7):

\[\frac{-z^{-3}}{3}-2Az^{-1}+A^{2}z+C\]

OpenStudy (anonymous):

yup!

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