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An integer is chosen at random from the first 40 positive integers. What is the probability that the integer chosen is divisible by 6 or 8?
0.6
what is that as a fraction
How did you get 0.6?
I got \[\frac{9}{40}\]
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i ment 10/40 or 1/4
every 4th multiple of 6 should also be divible by 8 or (to think of it in a different way) every 3rd multiple of 8 should be divisible by 6. 6*4k = 2*4*3k = 8*3k => multiple of 8 8*3k = 4*2*3k = 6*4k => multiple of 6
I get 9 numbers not 10. \[\{6,8,12,16,18,24,30,32,36\}\]
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